Base | Representation |
---|---|
bin | 111101001101000011… |
… | …0111100011011011000 |
3 | 110120020220020221112211 |
4 | 1322122012330123120 |
5 | 4123134214434040 |
6 | 140214042044504 |
7 | 12332033035036 |
oct | 1723206743330 |
9 | 416226227484 |
10 | 131434530520 |
11 | 50817403147 |
12 | 215811a9734 |
13 | c518153467 |
14 | 650bc09556 |
15 | 3643c798ea |
hex | 1e9a1bc6d8 |
131434530520 has 32 divisors (see below), whose sum is σ = 298776441600. Its totient is φ = 52031812608.
The previous prime is 131434530361. The next prime is 131434530571. The reversal of 131434530520 is 25035434131.
It is a super-2 number, since 2×1314345305202 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 16933560 + ... + 16941319.
It is an arithmetic number, because the mean of its divisors is an integer number (9336763800).
Almost surely, 2131434530520 is an apocalyptic number.
131434530520 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
131434530520 is an abundant number, since it is smaller than the sum of its proper divisors (167341911080).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131434530520 is a wasteful number, since it uses less digits than its factorization.
131434530520 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 33874987 (or 33874983 counting only the distinct ones).
The product of its (nonzero) digits is 21600, while the sum is 31.
Adding to 131434530520 its reverse (25035434131), we get a palindrome (156469964651).
The spelling of 131434530520 in words is "one hundred thirty-one billion, four hundred thirty-four million, five hundred thirty thousand, five hundred twenty".
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