13144013 has 4 divisors (see below), whose sum is σ = 13182240. Its totient is φ = 13105788.

The previous prime is 13144007. The next prime is 13144049. The reversal of 13144013 is 31044131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 31044131 = 167 ⋅185893.

It is a cyclic number.

It is not a de Polignac number, because 13144013 - 2⁴ = 13143997 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 13143982 and 13144000.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13144073) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 18593 + ... + 19286.

It is an arithmetic number, because the mean of its divisors is an integer number (3295560).

Almost surely, 2^13144013 is an apocalyptic number.

It is an amenable number.

13144013 is a deficient number, since it is larger than the sum of its proper divisors (38227).

13144013 is an equidigital number, since it uses as much as digits as its factorization.

13144013 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 38226.

The product of its (nonzero) digits is 144, while the sum is 17.

The square root of 13144013 is about 3625.4672802275. The cubic root of 13144013 is about 235.9985456676.

Adding to 13144013 its reverse (31044131), we get a palindrome (44188144).

It can be divided in two parts, 131 and 44013, that added together give a palindrome (44144).

The spelling of 13144013 in words is "thirteen million, one hundred forty-four thousand, thirteen".