13144015312542 has 48 divisors (see below), whose sum is σ = 31270729259952. Its totient is φ = 4123612644480.

The previous prime is 13144015312531. The next prime is 13144015312607. The reversal of 13144015312542 is 24521351044131.

13144015312542 is a `hidden beast` number, since 1 + 3 + 1 + 440 + 1 + 53 + 125 + 42 = 666.

It is a junction number, because it is equal to n+sod(n) for n = 13144015312497 and 13144015312506.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 795441709 + ... + 795458232.

It is an arithmetic number, because the mean of its divisors is an integer number (651473526249).

Almost surely, 2^{13144015312542} is an apocalyptic number.

13144015312542 is an abundant number, since it is smaller than the sum of its proper divisors (18126713947410).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13144015312542 is a wasteful number, since it uses less digits than its factorization.

13144015312542 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1590899975 (or 1590899963 counting only the distinct ones).

The product of its (nonzero) digits is 57600, while the sum is 36.

Adding to 13144015312542 its reverse (24521351044131), we get a palindrome (37665366356673).

The spelling of 13144015312542 in words is "thirteen trillion, one hundred forty-four billion, fifteen million, three hundred twelve thousand, five hundred forty-two".