131440432541 has 4 divisors (see below), whose sum is σ = 143389562784. Its totient is φ = 119491302300.

The previous prime is 131440432537. The next prime is 131440432589. The reversal of 131440432541 is 145234044131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 145234044131 = 11 ⋅13203094921.

It is a cyclic number.

It is not a de Polignac number, because 131440432541 - 2² = 131440432537 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 131440432498 and 131440432507.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131440432511) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5974565105 + ... + 5974565126.

It is an arithmetic number, because the mean of its divisors is an integer number (35847390696).

Almost surely, 2^131440432541 is an apocalyptic number.

131440432541 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

131440432541 is a deficient number, since it is larger than the sum of its proper divisors (11949130243).

131440432541 is a wasteful number, since it uses less digits than its factorization.

131440432541 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 11949130242.

The product of its (nonzero) digits is 23040, while the sum is 32.

Adding to 131440432541 its reverse (145234044131), we get a palindrome (276674476672).

The spelling of 131440432541 in words is "one hundred thirty-one billion, four hundred forty million, four hundred thirty-two thousand, five hundred forty-one".