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131452511054021 is a prime number
BaseRepresentation
bin11101111000111000101100…
…001110011110100011000101
3122020102201220111211000102022
4131320320230032132203011
5114212204220312212041
61143324241102452525
736455062524022463
oct3570705416364305
9566381814730368
10131452511054021
1138980773591623
12128b0463b94145
135846bc322b751
14246649a7c5833
15102e5ac75e24b
hex778e2c39e8c5

131452511054021 has 2 divisors, whose sum is σ = 131452511054022. Its totient is φ = 131452511054020.

The previous prime is 131452511053991. The next prime is 131452511054023. The reversal of 131452511054021 is 120450115254131.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 113758457709121 + 17694053344900 = 10665761^2 + 4206430^2 .

It is a cyclic number.

It is not a de Polignac number, because 131452511054021 - 26 = 131452511053957 is a prime.

Together with 131452511054023, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131452511054023) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65726255527010 + 65726255527011.

It is an arithmetic number, because the mean of its divisors is an integer number (65726255527011).

Almost surely, 2131452511054021 is an apocalyptic number.

It is an amenable number.

131452511054021 is a deficient number, since it is larger than the sum of its proper divisors (1).

131452511054021 is an equidigital number, since it uses as much as digits as its factorization.

131452511054021 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 24000, while the sum is 35.

The spelling of 131452511054021 in words is "one hundred thirty-one trillion, four hundred fifty-two billion, five hundred eleven million, fifty-four thousand, twenty-one".