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13147200000 = 2932551183
BaseRepresentation
bin11000011111010001…
…00101101000000000
31020221020202221220100
430033220211220000
5203411140400000
610012330042400
7643541233104
oct141750455000
936836687810
1013147200000
115637284a50
12266ab79400
131316a302ac
148ca125904
1551e32ba00
hex30fa25a00

13147200000 has 720 divisors, whose sum is σ = 52361461152. Its totient is φ = 3148800000.

The previous prime is 13147199959. The next prime is 13147200013. The reversal of 13147200000 is 274131.

It is a tau number, because it is divible by the number of its divisors (720).

It is a Harshad number since it is a multiple of its sum of digits (18).

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 71 ways as a sum of consecutive naturals, for example, 158399959 + ... + 158400041.

Almost surely, 213147200000 is an apocalyptic number.

13147200000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13147200000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (26180730576).

13147200000 is an abundant number, since it is smaller than the sum of its proper divisors (39214261152).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13147200000 is an frugal number, since it uses more digits than its factorization.

13147200000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 143 (or 104 counting only the distinct ones).

The product of its (nonzero) digits is 168, while the sum is 18.

Adding to 13147200000 its reverse (274131), we get a palindrome (13147474131).

The spelling of 13147200000 in words is "thirteen billion, one hundred forty-seven million, two hundred thousand".