13149766424981 has 4 divisors (see below), whose sum is σ = 13149862968000. Its totient is φ = 13149669881964.

The previous prime is 13149766424849. The next prime is 13149766424987. The reversal of 13149766424981 is 18942466794131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13149766424981 - 2¹⁰ = 13149766423957 is a prime.

It is a super-2 number, since 2×13149766424981² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a Curzon number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13149766424987) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 48066911 + ... + 48339708.

It is an arithmetic number, because the mean of its divisors is an integer number (3287465742000).

Almost surely, 2^{13149766424981} is an apocalyptic number.

It is an amenable number.

13149766424981 is a deficient number, since it is larger than the sum of its proper divisors (96543019).

13149766424981 is an equidigital number, since it uses as much as digits as its factorization.

13149766424981 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 96543018.

The product of its digits is 62705664, while the sum is 65.

The spelling of 13149766424981 in words is "thirteen trillion, one hundred forty-nine billion, seven hundred sixty-six million, four hundred twenty-four thousand, nine hundred eighty-one".