Base | Representation |
---|---|
bin | 11000011111100111… |
… | …01100111000101000 |
3 | 1020221110020222020002 |
4 | 30033303230320220 |
5 | 203412412111240 |
6 | 10012512322132 |
7 | 643605055541 |
oct | 141763547050 |
9 | 36843228202 |
10 | 13150113320 |
11 | 5638994853 |
12 | 266bb43348 |
13 | 1317510356 |
14 | 8ca6834c8 |
15 | 51e704d15 |
hex | 30fcece28 |
13150113320 has 16 divisors (see below), whose sum is σ = 29587755060. Its totient is φ = 5260045312.
The previous prime is 13150113299. The next prime is 13150113323. The reversal of 13150113320 is 2331105131.
It can be written as a sum of positive squares in 2 ways, for example, as 12605451076 + 544662244 = 112274^2 + 23338^2 .
It is a Harshad number since it is a multiple of its sum of digits (20).
It is a junction number, because it is equal to n+sod(n) for n = 13150113292 and 13150113301.
It is not an unprimeable number, because it can be changed into a prime (13150113323) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 164376377 + ... + 164376456.
Almost surely, 213150113320 is an apocalyptic number.
13150113320 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13150113320 is an abundant number, since it is smaller than the sum of its proper divisors (16437641740).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13150113320 is a wasteful number, since it uses less digits than its factorization.
13150113320 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 328752844 (or 328752840 counting only the distinct ones).
The product of its (nonzero) digits is 270, while the sum is 20.
Adding to 13150113320 its reverse (2331105131), we get a palindrome (15481218451).
The spelling of 13150113320 in words is "thirteen billion, one hundred fifty million, one hundred thirteen thousand, three hundred twenty".
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