Base | Representation |
---|---|
bin | 10011001000110010111… |
… | …000000001110000100010 |
3 | 11122201112112010212101200 |
4 | 103020302320001300202 |
5 | 133021323031300032 |
6 | 2444053235142030 |
7 | 164004511440156 |
oct | 23106270016042 |
9 | 4581475125350 |
10 | 1315113540642 |
11 | 467811343a50 |
12 | 192a64a44916 |
13 | 970263182b5 |
14 | 4791a8c7066 |
15 | 24320bb647c |
hex | 13232e01c22 |
1315113540642 has 48 divisors (see below), whose sum is σ = 3109012163712. Its totient is φ = 398447206560.
The previous prime is 1315113540617. The next prime is 1315113540677. The reversal of 1315113540642 is 2460453115131.
1315113540642 is a `hidden beast` number, since 1 + 3 + 1 + 5 + 1 + 1 + 3 + 5 + 4 + 0 + 642 = 666.
It is a junction number, because it is equal to n+sod(n) for n = 1315113540597 and 1315113540606.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 502663 + ... + 1697909.
It is an arithmetic number, because the mean of its divisors is an integer number (64771086744).
Almost surely, 21315113540642 is an apocalyptic number.
1315113540642 is an abundant number, since it is smaller than the sum of its proper divisors (1793898623070).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1315113540642 is a wasteful number, since it uses less digits than its factorization.
1315113540642 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1200823 (or 1200820 counting only the distinct ones).
The product of its (nonzero) digits is 43200, while the sum is 36.
Adding to 1315113540642 its reverse (2460453115131), we get a palindrome (3775566655773).
The spelling of 1315113540642 in words is "one trillion, three hundred fifteen billion, one hundred thirteen million, five hundred forty thousand, six hundred forty-two".
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