Base | Representation |
---|---|
bin | 11101111001110111111011… |
… | …111111111001111101101000 |
3 | 122020200020012022010021001221 |
4 | 131321313323333321331220 |
5 | 114214312310334421040 |
6 | 1143415351505151424 |
7 | 36463015435334521 |
oct | 3571677377717550 |
9 | 566606168107057 |
10 | 131520421404520 |
11 | 389a7552175035 |
12 | 1290165702b574 |
13 | 58504267704b5 |
14 | 246989da87848 |
15 | 103123469e74a |
hex | 779dfbff9f68 |
131520421404520 has 32 divisors (see below), whose sum is σ = 297692929900800. Its totient is φ = 52293149585728.
The previous prime is 131520421404511. The next prime is 131520421404521. The reversal of 131520421404520 is 25404124025131.
It is not an unprimeable number, because it can be changed into a prime (131520421404521) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 9844336240 + ... + 9844349599.
It is an arithmetic number, because the mean of its divisors is an integer number (9302904059400).
Almost surely, 2131520421404520 is an apocalyptic number.
131520421404520 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
131520421404520 is an abundant number, since it is smaller than the sum of its proper divisors (166172508496280).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131520421404520 is a wasteful number, since it uses less digits than its factorization.
131520421404520 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 19688686017 (or 19688686013 counting only the distinct ones).
The product of its (nonzero) digits is 38400, while the sum is 34.
Adding to 131520421404520 its reverse (25404124025131), we get a palindrome (156924545429651).
The spelling of 131520421404520 in words is "one hundred thirty-one trillion, five hundred twenty billion, four hundred twenty-one million, four hundred four thousand, five hundred twenty".
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