Base | Representation |
---|---|
bin | 1011111101100101011100… |
… | …1000110011011101100000 |
3 | 1201120101021220202201210022 |
4 | 2333121113020303131200 |
5 | 3210443112324123310 |
6 | 43550124514053012 |
7 | 2525150654360402 |
oct | 277312710633540 |
9 | 51511256681708 |
10 | 13152651786080 |
11 | 4211010053a94 |
12 | 15850a457a168 |
13 | 74539c73cb61 |
14 | 33683da58b72 |
15 | 17c1e5e75a55 |
hex | bf657233760 |
13152651786080 has 24 divisors (see below), whose sum is σ = 31073139844992. Its totient is φ = 5261060714368.
The previous prime is 13152651786013. The next prime is 13152651786083. The reversal of 13152651786080 is 8068715625131.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13152651786083) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 41102036672 + ... + 41102036991.
It is an arithmetic number, because the mean of its divisors is an integer number (1294714160208).
Almost surely, 213152651786080 is an apocalyptic number.
13152651786080 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13152651786080 is an abundant number, since it is smaller than the sum of its proper divisors (17920488058912).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13152651786080 is an equidigital number, since it uses as much as digits as its factorization.
13152651786080 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 82204073678 (or 82204073670 counting only the distinct ones).
The product of its (nonzero) digits is 2419200, while the sum is 53.
The spelling of 13152651786080 in words is "thirteen trillion, one hundred fifty-two billion, six hundred fifty-one million, seven hundred eighty-six thousand, eighty".
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