Base | Representation |
---|---|
bin | 11101111010000100111101… |
… | …110011101111010110001111 |
3 | 122020201120022012220112201222 |
4 | 131322010331303233112033 |
5 | 114220024433031212310 |
6 | 1143430023550153555 |
7 | 36464022211055240 |
oct | 3572047563572617 |
9 | 566646265815658 |
10 | 131534410413455 |
11 | 38a02480646545 |
12 | 129042bbab28bb |
13 | 5851845a0168a |
14 | 246a4298dccc7 |
15 | 10317a2861055 |
hex | 77a13dcef58f |
131534410413455 has 64 divisors (see below), whose sum is σ = 193116143582208. Its totient is φ = 83953895700480.
The previous prime is 131534410413397. The next prime is 131534410413467. The reversal of 131534410413455 is 554314014435131.
It is not a de Polignac number, because 131534410413455 - 220 = 131534409364879 is a prime.
It is a super-2 number, since 2×1315344104134552 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 19958144 + ... + 25717626.
It is an arithmetic number, because the mean of its divisors is an integer number (3017439743472).
Almost surely, 2131534410413455 is an apocalyptic number.
131534410413455 is a deficient number, since it is larger than the sum of its proper divisors (61581733168753).
131534410413455 is a wasteful number, since it uses less digits than its factorization.
131534410413455 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5759936.
The product of its (nonzero) digits is 864000, while the sum is 44.
Adding to 131534410413455 its reverse (554314014435131), we get a palindrome (685848424848586).
The spelling of 131534410413455 in words is "one hundred thirty-one trillion, five hundred thirty-four billion, four hundred ten million, four hundred thirteen thousand, four hundred fifty-five".
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