Base | Representation |
---|---|
bin | 111101010000001011… |
… | …0110101000010010111 |
3 | 110120112012111201121102 |
4 | 1322200112311002113 |
5 | 4123343033422342 |
6 | 140232304540315 |
7 | 12334445044052 |
oct | 1724026650227 |
9 | 416465451542 |
10 | 131539357847 |
11 | 508705a14a7 |
12 | 215b032169b |
13 | c533a97271 |
14 | 651bad5a99 |
15 | 364d084832 |
hex | 1ea05b5097 |
131539357847 has 2 divisors, whose sum is σ = 131539357848. Its totient is φ = 131539357846.
The previous prime is 131539357837. The next prime is 131539357849. The reversal of 131539357847 is 748753935131.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 131539357847 - 218 = 131539095703 is a prime.
It is a super-2 number, since 2×1315393578472 (a number of 23 digits) contains 22 as substring.
Together with 131539357849, it forms a pair of twin primes.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 131539357792 and 131539357801.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131539357849) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65769678923 + 65769678924.
It is an arithmetic number, because the mean of its divisors is an integer number (65769678924).
Almost surely, 2131539357847 is an apocalyptic number.
131539357847 is a deficient number, since it is larger than the sum of its proper divisors (1).
131539357847 is an equidigital number, since it uses as much as digits as its factorization.
131539357847 is an evil number, because the sum of its binary digits is even.
The product of its digits is 9525600, while the sum is 56.
The spelling of 131539357847 in words is "one hundred thirty-one billion, five hundred thirty-nine million, three hundred fifty-seven thousand, eight hundred forty-seven".
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