Base | Representation |
---|---|
bin | 1111101011101… |
… | …01111100111011 |
3 | 100011112200201021 |
4 | 13311311330323 |
5 | 232134231011 |
6 | 21015403311 |
7 | 3155125441 |
oct | 765657473 |
9 | 304480637 |
10 | 131555131 |
11 | 68294354 |
12 | 38083537 |
13 | 21341596 |
14 | 13686b91 |
15 | b839471 |
hex | 7d75f3b |
131555131 has 2 divisors, whose sum is σ = 131555132. Its totient is φ = 131555130.
The previous prime is 131555117. The next prime is 131555143.
It is a happy number.
131555131 is nontrivially palindromic in base 10.
It is a strong prime.
It is a palprime.
It is a cyclic number.
It is not a de Polignac number, because 131555131 - 27 = 131555003 is a prime.
It is a super-2 number, since 2×1315551312 = 34613504984854322, which contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 131555096 and 131555105.
It is not a weakly prime, because it can be changed into another prime (131555111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65777565 + 65777566.
It is an arithmetic number, because the mean of its divisors is an integer number (65777566).
Almost surely, 2131555131 is an apocalyptic number.
131555131 is a deficient number, since it is larger than the sum of its proper divisors (1).
131555131 is an equidigital number, since it uses as much as digits as its factorization.
131555131 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1125, while the sum is 25.
The square root of 131555131 is about 11469.7485151158. The cubic root of 131555131 is about 508.5916946140.
The spelling of 131555131 in words is "one hundred thirty-one million, five hundred fifty-five thousand, one hundred thirty-one".
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