13157439897600 has 1320 divisors, whose sum is σ = 51824491879050. Its totient is φ = 3302259425280.

The previous prime is 13157439897541. The next prime is 13157439897607. The reversal of 13157439897600 is 679893475131.

13157439897600 is a `hidden beast` number, since 1 + 3 + 1 + 57 + 439 + 8 + 97 + 60 + 0 = 666.

It can be written as a sum of positive squares in 3 ways, for example, as 11284439629824 + 1873000267776 = 3359232^2 + 1368576^2 .

It is a super-3 number, since 3×13157439897600³ (a number of 40 digits) contains 333 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13157439897607) by changing a digit.

It is a polite number, since it can be written in 65 ways as a sum of consecutive naturals, for example, 773967052792 + ... + 773967052808.

Almost surely, 2^{13157439897600} is an apocalyptic number.

13157439897600 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13157439897600, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (25912245939525).

13157439897600 is an abundant number, since it is smaller than the sum of its proper divisors (38667051981450).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13157439897600 is an frugal number, since it uses more digits than its factorization.

13157439897600 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 95 (or 27 counting only the distinct ones).

The product of its (nonzero) digits is 34292160, while the sum is 63.

The spelling of 13157439897600 in words is "thirteen trillion, one hundred fifty-seven billion, four hundred thirty-nine million, eight hundred ninety-seven thousand, six hundred".