Base | Representation |
---|---|
bin | 10011001001110010001… |
… | …110100110001111111111 |
3 | 11122211021121010211100201 |
4 | 103021302032212033333 |
5 | 133031012131000022 |
6 | 2444350524304331 |
7 | 164043035665255 |
oct | 23116216461777 |
9 | 4584247124321 |
10 | 1316176421887 |
11 | 4682073063a8 |
12 | 1931009a20a7 |
13 | 971655a0a02 |
14 | 479bbb225d5 |
15 | 24384169127 |
hex | 132723a63ff |
1316176421887 has 2 divisors, whose sum is σ = 1316176421888. Its totient is φ = 1316176421886.
The previous prime is 1316176421863. The next prime is 1316176421891. The reversal of 1316176421887 is 7881246716131.
It is a happy number.
It is a strong prime.
It is an emirp because it is prime and its reverse (7881246716131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1316176421887 - 27 = 1316176421759 is a prime.
It is a super-3 number, since 3×13161764218873 (a number of 37 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1316176421387) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 658088210943 + 658088210944.
It is an arithmetic number, because the mean of its divisors is an integer number (658088210944).
Almost surely, 21316176421887 is an apocalyptic number.
1316176421887 is a deficient number, since it is larger than the sum of its proper divisors (1).
1316176421887 is an equidigital number, since it uses as much as digits as its factorization.
1316176421887 is an evil number, because the sum of its binary digits is even.
The product of its digits is 2709504, while the sum is 55.
The spelling of 1316176421887 in words is "one trillion, three hundred sixteen billion, one hundred seventy-six million, four hundred twenty-one thousand, eight hundred eighty-seven".
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