Base | Representation |
---|---|
bin | 10011001001110010001… |
… | …110100110010000000011 |
3 | 11122211021121010211100212 |
4 | 103021302032212100003 |
5 | 133031012131000031 |
6 | 2444350524304335 |
7 | 164043035665262 |
oct | 23116216462003 |
9 | 4584247124325 |
10 | 1316176421891 |
11 | 468207306401 |
12 | 1931009a20ab |
13 | 971655a0a06 |
14 | 479bbb225d9 |
15 | 2438416912b |
hex | 132723a6403 |
1316176421891 has 2 divisors, whose sum is σ = 1316176421892. Its totient is φ = 1316176421890.
The previous prime is 1316176421887. The next prime is 1316176421933. The reversal of 1316176421891 is 1981246716131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1316176421891 - 22 = 1316176421887 is a prime.
It is a super-3 number, since 3×13161764218913 (a number of 37 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (1316176421831) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 658088210945 + 658088210946.
It is an arithmetic number, because the mean of its divisors is an integer number (658088210946).
Almost surely, 21316176421891 is an apocalyptic number.
1316176421891 is a deficient number, since it is larger than the sum of its proper divisors (1).
1316176421891 is an equidigital number, since it uses as much as digits as its factorization.
1316176421891 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 435456, while the sum is 50.
The spelling of 1316176421891 in words is "one trillion, three hundred sixteen billion, one hundred seventy-six million, four hundred twenty-one thousand, eight hundred ninety-one".
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