Search a number
-
+
131644384757 is a prime number
BaseRepresentation
bin111101010011010011…
…1011110010111110101
3110120210112010122102222
41322212213132113311
54124101430303012
6140250540012125
712340161544004
oct1724647362765
9416715118388
10131644384757
11509149067a6
122161b531045
13c54c77ab72
14652ba34c3b
1536573cd972
hex1ea69de5f5

131644384757 has 2 divisors, whose sum is σ = 131644384758. Its totient is φ = 131644384756.

The previous prime is 131644384693. The next prime is 131644384759. The reversal of 131644384757 is 757483446131.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 119488440241 + 12155944516 = 345671^2 + 110254^2 .

It is an emirp because it is prime and its reverse (757483446131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 131644384757 - 26 = 131644384693 is a prime.

Together with 131644384759, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 131644384699 and 131644384708.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131644384759) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65822192378 + 65822192379.

It is an arithmetic number, because the mean of its divisors is an integer number (65822192379).

Almost surely, 2131644384757 is an apocalyptic number.

It is an amenable number.

131644384757 is a deficient number, since it is larger than the sum of its proper divisors (1).

131644384757 is an equidigital number, since it uses as much as digits as its factorization.

131644384757 is an evil number, because the sum of its binary digits is even.

The product of its digits is 6773760, while the sum is 53.

The spelling of 131644384757 in words is "one hundred thirty-one billion, six hundred forty-four million, three hundred eighty-four thousand, seven hundred fifty-seven".