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131940364800 = 2935223316179
BaseRepresentation
bin111101011100001000…
…0100011001000000000
3110121120011001222201210
41322320100203020000
54130203213133200
6140340151530120
712350414411406
oct1727020431000
9417504058653
10131940364800
1150a56994a02
12216a2689940
13c598b9bc9a
14655907d476
153673396650
hex1eb8423200

131940364800 has 960 divisors, whose sum is σ = 483214786560. Its totient is φ = 31629312000.

The previous prime is 131940364799. The next prime is 131940364819. The reversal of 131940364800 is 8463049131.

It is a tau number, because it is divible by the number of its divisors (960).

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 1670131161 + ... + 1670131239.

It is an arithmetic number, because the mean of its divisors is an integer number (503348736).

Almost surely, 2131940364800 is an apocalyptic number.

131940364800 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 131940364800, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (241607393280).

131940364800 is an abundant number, since it is smaller than the sum of its proper divisors (351274421760).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131940364800 is a wasteful number, since it uses less digits than its factorization.

131940364800 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 225 (or 204 counting only the distinct ones).

The product of its (nonzero) digits is 62208, while the sum is 39.

The spelling of 131940364800 in words is "one hundred thirty-one billion, nine hundred forty million, three hundred sixty-four thousand, eight hundred".