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131979335 = 526395867
BaseRepresentation
bin1111101110111…
…01100001000111
3100012100020121112
413313131201013
5232241314320
621032435235
73161543255
oct767354107
9305306545
10131979335
1168554034
1238248b1b
132145c6a7
14137575d5
15b8beec5
hex7ddd847

131979335 has 4 divisors (see below), whose sum is σ = 158375208. Its totient is φ = 105583464.

The previous prime is 131979317. The next prime is 131979371. The reversal of 131979335 is 533979131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-131979335 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 131979292 and 131979301.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13197929 + ... + 13197938.

It is an arithmetic number, because the mean of its divisors is an integer number (39593802).

Almost surely, 2131979335 is an apocalyptic number.

131979335 is a deficient number, since it is larger than the sum of its proper divisors (26395873).

131979335 is an equidigital number, since it uses as much as digits as its factorization.

131979335 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 26395872.

The product of its digits is 76545, while the sum is 41.

The square root of 131979335 is about 11488.2259291851. The cubic root of 131979335 is about 509.1377651726.

The spelling of 131979335 in words is "one hundred thirty-one million, nine hundred seventy-nine thousand, three hundred thirty-five".

Divisors: 1 5 26395867 131979335