Base | Representation |
---|---|
bin | 1100000000010101111110… |
… | …1101101110010000010111 |
3 | 1201201220121111122210020221 |
4 | 3000011133231232100113 |
5 | 3212232140310301241 |
6 | 44024003110535211 |
7 | 2531446206314431 |
oct | 300053755562027 |
9 | 51656544583227 |
10 | 13200040322071 |
11 | 422a118701519 |
12 | 159230a967507 |
13 | 7499b24548b5 |
14 | 338c57601651 |
15 | 17d56b4235d1 |
hex | c015fb6e417 |
13200040322071 has 2 divisors, whose sum is σ = 13200040322072. Its totient is φ = 13200040322070.
The previous prime is 13200040322059. The next prime is 13200040322089. The reversal of 13200040322071 is 17022304000231.
It is a happy number.
13200040322071 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is an emirp because it is prime and its reverse (17022304000231) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13200040322071 - 231 = 13197892838423 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13200040322011) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6600020161035 + 6600020161036.
It is an arithmetic number, because the mean of its divisors is an integer number (6600020161036).
Almost surely, 213200040322071 is an apocalyptic number.
13200040322071 is a deficient number, since it is larger than the sum of its proper divisors (1).
13200040322071 is an equidigital number, since it uses as much as digits as its factorization.
13200040322071 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2016, while the sum is 25.
The spelling of 13200040322071 in words is "thirteen trillion, two hundred billion, forty million, three hundred twenty-two thousand, seventy-one".
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