Base | Representation |
---|---|
bin | 111101011101111010… |
… | …1100100111110111111 |
3 | 110121201100001021012022 |
4 | 1322323311210332333 |
5 | 4130314100402031 |
6 | 140350134430355 |
7 | 12352043626133 |
oct | 1727365447677 |
9 | 417640037168 |
10 | 132000403391 |
11 | 50a8787187a |
12 | 216ba8023bb |
13 | c5a846068c |
14 | 656302b3c3 |
15 | 36787a597b |
hex | 1ebbd64fbf |
132000403391 has 2 divisors, whose sum is σ = 132000403392. Its totient is φ = 132000403390.
The previous prime is 132000403357. The next prime is 132000403393. The reversal of 132000403391 is 193304000231.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 132000403391 - 222 = 131996209087 is a prime.
Together with 132000403393, it forms a pair of twin primes.
It is a Chen prime.
It is a self number, because there is not a number n which added to its sum of digits gives 132000403391.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (132000403393) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66000201695 + 66000201696.
It is an arithmetic number, because the mean of its divisors is an integer number (66000201696).
Almost surely, 2132000403391 is an apocalyptic number.
132000403391 is a deficient number, since it is larger than the sum of its proper divisors (1).
132000403391 is an equidigital number, since it uses as much as digits as its factorization.
132000403391 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1944, while the sum is 26.
The spelling of 132000403391 in words is "one hundred thirty-two billion, four hundred three thousand, three hundred ninety-one".
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