Base | Representation |
---|---|
bin | 111101011101111100… |
… | …1000101100011000001 |
3 | 110121201101202222221100 |
4 | 1322323321011203001 |
5 | 4130314314320301 |
6 | 140350210245013 |
7 | 12352054506606 |
oct | 1727371054301 |
9 | 417641688840 |
10 | 132001323201 |
11 | 50a8833a950 |
12 | 216bab86769 |
13 | c5a86c3247 |
14 | 65631ca6ad |
15 | 36788d8286 |
hex | 1ebbe458c1 |
132001323201 has 24 divisors (see below), whose sum is σ = 211106604384. Its totient is φ = 78806756160.
The previous prime is 132001323187. The next prime is 132001323203. The reversal of 132001323201 is 102323100231.
132001323201 is a `hidden beast` number, since 1 + 320 + 0 + 1 + 323 + 20 + 1 = 666.
It is not a de Polignac number, because 132001323201 - 214 = 132001306817 is a prime.
It is not an unprimeable number, because it can be changed into a prime (132001323203) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 9943716 + ... + 9956981.
It is an arithmetic number, because the mean of its divisors is an integer number (8796108516).
Almost surely, 2132001323201 is an apocalyptic number.
132001323201 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
It is an amenable number.
132001323201 is a deficient number, since it is larger than the sum of its proper divisors (79105281183).
132001323201 is a wasteful number, since it uses less digits than its factorization.
132001323201 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 19900781 (or 19900778 counting only the distinct ones).
The product of its (nonzero) digits is 216, while the sum is 18.
Adding to 132001323201 its reverse (102323100231), we get a palindrome (234324423432).
The spelling of 132001323201 in words is "one hundred thirty-two billion, one million, three hundred twenty-three thousand, two hundred one".
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