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1320034 = 2679851
BaseRepresentation
bin101000010010001100010
32111001202011
411002101202
5314220114
644143134
714135332
oct5022142
92431664
101320034
11821841
12537aaa
13372ab1
142650c2
151b11c4
hex142462

1320034 has 8 divisors (see below), whose sum is σ = 2009808. Its totient is φ = 650100.

The previous prime is 1320031. The next prime is 1320037. The reversal of 1320034 is 4300231.

It is an interprime number because it is at equal distance from previous prime (1320031) and next prime (1320037).

It is a sphenic number, since it is the product of 3 distinct primes.

It is a super-3 number, since 3×13200343 = 6900437188133397912, which contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 1319996 and 1320023.

It is not an unprimeable number, because it can be changed into a prime (1320031) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (7) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4792 + ... + 5059.

It is an arithmetic number, because the mean of its divisors is an integer number (251226).

21320034 is an apocalyptic number.

1320034 is a deficient number, since it is larger than the sum of its proper divisors (689774).

1320034 is an equidigital number, since it uses as much as digits as its factorization.

1320034 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 9920.

The product of its (nonzero) digits is 72, while the sum is 13.

The square root of 1320034 is about 1148.9273258131. The cubic root of 1320034 is about 109.6970728760.

Adding to 1320034 its reverse (4300231), we get a palindrome (5620265).

The spelling of 1320034 in words is "one million, three hundred twenty thousand, thirty-four".

Divisors: 1 2 67 134 9851 19702 660017 1320034