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1320044043320 = 2351912771360141
BaseRepresentation
bin10011001101011000110…
…000011001110000111000
311200012021010202100112222
4103031120300121300320
5133111422233341240
62450230405023212
7164240631143432
oct23153060316070
94605233670488
101320044043320
114699114a3652
12193a000b4b08
13976309530c2
1447c67657652
152450d990eb5
hex13358c19c38

1320044043320 has 64 divisors (see below), whose sum is σ = 3128870656800. Its totient is φ = 499835128320.

The previous prime is 1320044043317. The next prime is 1320044043323. The reversal of 1320044043320 is 233404400231.

It is an interprime number because it is at equal distance from previous prime (1320044043317) and next prime (1320044043323).

It is a super-2 number, since 2×13200440433202 (a number of 25 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 1320044043320.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1320044043323) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 290450 + ... + 1650590.

Almost surely, 21320044043320 is an apocalyptic number.

1320044043320 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1320044043320, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1564435328400).

1320044043320 is an abundant number, since it is smaller than the sum of its proper divisors (1808826613480).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1320044043320 is a wasteful number, since it uses less digits than its factorization.

1320044043320 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1361448 (or 1361444 counting only the distinct ones).

The product of its (nonzero) digits is 6912, while the sum is 26.

Adding to 1320044043320 its reverse (233404400231), we get a palindrome (1553448443551).

The spelling of 1320044043320 in words is "one trillion, three hundred twenty billion, forty-four million, forty-three thousand, three hundred twenty".

Divisors: 1 2 4 5 8 10 19 20 38 40 76 95 152 190 380 760 1277 2554 5108 6385 10216 12770 24263 25540 48526 51080 97052 121315 194104 242630 485260 970520 1360141 2720282 5440564 6800705 10881128 13601410 25842679 27202820 51685358 54405640 103370716 129213395 206741432 258426790 516853580 1033707160 1736900057 3473800114 6947600228 8684500285 13895200456 17369000570 33001101083 34738001140 66002202166 69476002280 132004404332 165005505415 264008808664 330011010830 660022021660 1320044043320