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13201100000 = 25551121091
BaseRepresentation
bin11000100101101100…
…01100110011100000
31021002000012100210122
430102312030303200
5204013440200000
610021533215412
7645064333004
oct142266146340
937060170718
1013201100000
115664749900
122685031568
131324c5289a
148d3356704
15523e27085
hex312d8cce0

13201100000 has 216 divisors, whose sum is σ = 35739384408. Its totient is φ = 4796000000.

The previous prime is 13201099999. The next prime is 13201100021. The reversal of 13201100000 is 110231.

It is a Harshad number since it is a multiple of its sum of digits (8).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 35 ways as a sum of consecutive naturals, for example, 12099455 + ... + 12100545.

It is an arithmetic number, because the mean of its divisors is an integer number (165460113).

Almost surely, 213201100000 is an apocalyptic number.

13201100000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13201100000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (17869692204).

13201100000 is an abundant number, since it is smaller than the sum of its proper divisors (22538284408).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13201100000 is an equidigital number, since it uses as much as digits as its factorization.

13201100000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1148 (or 1109 counting only the distinct ones).

The product of its (nonzero) digits is 6, while the sum is 8.

Adding to 13201100000 its reverse (110231), we get a palindrome (13201210231).

The spelling of 13201100000 in words is "thirteen billion, two hundred one million, one hundred thousand".