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132011814012 = 22313846229577
BaseRepresentation
bin111101011110010000…
…1000110110001111100
3110121202010111222121220
41322330201012301330
54130330011022022
6140351223153340
712352242622221
oct1727441066174
9417663458556
10132011814012
1150a93255841
12217025a5850
13c5aa927320
14656475b948
1536797ab85c
hex1ebc846c7c

132011814012 has 24 divisors (see below), whose sum is σ = 331721994576. Its totient is φ = 40619019648.

The previous prime is 132011813959. The next prime is 132011814037. The reversal of 132011814012 is 210418110231.

It is a super-2 number, since 2×1320118140122 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 423114633 + ... + 423114944.

It is an arithmetic number, because the mean of its divisors is an integer number (13821749774).

Almost surely, 2132011814012 is an apocalyptic number.

132011814012 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

132011814012 is an abundant number, since it is smaller than the sum of its proper divisors (199710180564).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

132011814012 is a wasteful number, since it uses less digits than its factorization.

132011814012 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 846229597 (or 846229595 counting only the distinct ones).

The product of its (nonzero) digits is 384, while the sum is 24.

Adding to 132011814012 its reverse (210418110231), we get a palindrome (342429924243).

The spelling of 132011814012 in words is "one hundred thirty-two billion, eleven million, eight hundred fourteen thousand, twelve".

Divisors: 1 2 3 4 6 12 13 26 39 52 78 156 846229577 1692459154 2538688731 3384918308 5077377462 10154754924 11000984501 22001969002 33002953503 44003938004 66005907006 132011814012