Base | Representation |
---|---|
bin | 111101011110010000… |
… | …1000110110001111100 |
3 | 110121202010111222121220 |
4 | 1322330201012301330 |
5 | 4130330011022022 |
6 | 140351223153340 |
7 | 12352242622221 |
oct | 1727441066174 |
9 | 417663458556 |
10 | 132011814012 |
11 | 50a93255841 |
12 | 217025a5850 |
13 | c5aa927320 |
14 | 656475b948 |
15 | 36797ab85c |
hex | 1ebc846c7c |
132011814012 has 24 divisors (see below), whose sum is σ = 331721994576. Its totient is φ = 40619019648.
The previous prime is 132011813959. The next prime is 132011814037. The reversal of 132011814012 is 210418110231.
It is a super-2 number, since 2×1320118140122 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 423114633 + ... + 423114944.
It is an arithmetic number, because the mean of its divisors is an integer number (13821749774).
Almost surely, 2132011814012 is an apocalyptic number.
132011814012 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
132011814012 is an abundant number, since it is smaller than the sum of its proper divisors (199710180564).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
132011814012 is a wasteful number, since it uses less digits than its factorization.
132011814012 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 846229597 (or 846229595 counting only the distinct ones).
The product of its (nonzero) digits is 384, while the sum is 24.
Adding to 132011814012 its reverse (210418110231), we get a palindrome (342429924243).
The spelling of 132011814012 in words is "one hundred thirty-two billion, eleven million, eight hundred fourteen thousand, twelve".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.069 sec. • engine limits •