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1320120202013 is a prime number
BaseRepresentation
bin10011001101011101010…
…010111011001100011101
311200012110110001121122022
4103031131102323030131
5133112101232431023
62450242125225525
7164242544400434
oct23153522731435
94605413047568
101320120202013
11469950490818
12193a217022a5
1397643669c12
1447c7380011b
15245154d67c8
hex1335d4bb31d

1320120202013 has 2 divisors, whose sum is σ = 1320120202014. Its totient is φ = 1320120202012.

The previous prime is 1320120201947. The next prime is 1320120202021. The reversal of 1320120202013 is 3102020210231.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1315822350649 + 4297851364 = 1147093^2 + 65558^2 .

It is a cyclic number.

It is not a de Polignac number, because 1320120202013 - 222 = 1320116007709 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1320120201982 and 1320120202000.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1320120202813) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 660060101006 + 660060101007.

It is an arithmetic number, because the mean of its divisors is an integer number (660060101007).

Almost surely, 21320120202013 is an apocalyptic number.

It is an amenable number.

1320120202013 is a deficient number, since it is larger than the sum of its proper divisors (1).

1320120202013 is an equidigital number, since it uses as much as digits as its factorization.

1320120202013 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 144, while the sum is 17.

Adding to 1320120202013 its reverse (3102020210231), we get a palindrome (4422140412244).

The spelling of 1320120202013 in words is "one trillion, three hundred twenty billion, one hundred twenty million, two hundred two thousand, thirteen".