Base | Representation |
---|---|
bin | 111101011110010011… |
… | …0000011010000011100 |
3 | 110121202012221211210120 |
4 | 1322330212003100130 |
5 | 4130330324012200 |
6 | 140351311034540 |
7 | 12352256631411 |
oct | 1727446032034 |
9 | 417665854716 |
10 | 132013110300 |
11 | 50a93a60755 |
12 | 21702b0ba50 |
13 | c5aac8c366 |
14 | 65649b8108 |
15 | 36799659a0 |
hex | 1ebc98341c |
132013110300 has 144 divisors (see below), whose sum is σ = 396328487520. Its totient is φ = 33898659840.
The previous prime is 132013110221. The next prime is 132013110301. The reversal of 132013110300 is 3011310231.
It is a super-2 number, since 2×1320131103002 (a number of 23 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (15).
It is a self number, because there is not a number n which added to its sum of digits gives 132013110300.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (132013110301) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 1015396 + ... + 1138004.
Almost surely, 2132013110300 is an apocalyptic number.
132013110300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 132013110300, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (198164243760).
132013110300 is an abundant number, since it is smaller than the sum of its proper divisors (264315377220).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
132013110300 is a wasteful number, since it uses less digits than its factorization.
132013110300 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 122760 (or 122753 counting only the distinct ones).
The product of its (nonzero) digits is 54, while the sum is 15.
Adding to 132013110300 its reverse (3011310231), we get a palindrome (135024420531).
The spelling of 132013110300 in words is "one hundred thirty-two billion, thirteen million, one hundred ten thousand, three hundred".
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