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132013110300 = 223523797122609
BaseRepresentation
bin111101011110010011…
…0000011010000011100
3110121202012221211210120
41322330212003100130
54130330324012200
6140351311034540
712352256631411
oct1727446032034
9417665854716
10132013110300
1150a93a60755
1221702b0ba50
13c5aac8c366
1465649b8108
1536799659a0
hex1ebc98341c

132013110300 has 144 divisors (see below), whose sum is σ = 396328487520. Its totient is φ = 33898659840.

The previous prime is 132013110221. The next prime is 132013110301. The reversal of 132013110300 is 3011310231.

It is a super-2 number, since 2×1320131103002 (a number of 23 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a self number, because there is not a number n which added to its sum of digits gives 132013110300.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (132013110301) by changing a digit.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 1015396 + ... + 1138004.

Almost surely, 2132013110300 is an apocalyptic number.

132013110300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 132013110300, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (198164243760).

132013110300 is an abundant number, since it is smaller than the sum of its proper divisors (264315377220).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

132013110300 is a wasteful number, since it uses less digits than its factorization.

132013110300 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 122760 (or 122753 counting only the distinct ones).

The product of its (nonzero) digits is 54, while the sum is 15.

Adding to 132013110300 its reverse (3011310231), we get a palindrome (135024420531).

The spelling of 132013110300 in words is "one hundred thirty-two billion, thirteen million, one hundred ten thousand, three hundred".

Divisors: 1 2 3 4 5 6 10 12 15 20 25 30 37 50 60 74 75 97 100 111 148 150 185 194 222 291 300 370 388 444 485 555 582 740 925 970 1110 1164 1455 1850 1940 2220 2425 2775 2910 3589 3700 4850 5550 5820 7178 7275 9700 10767 11100 14356 14550 17945 21534 29100 35890 43068 53835 71780 89725 107670 122609 179450 215340 245218 269175 358900 367827 490436 538350 613045 735654 1076700 1226090 1471308 1839135 2452180 3065225 3678270 4536533 6130450 7356540 9073066 9195675 11893073 12260900 13609599 18146132 18391350 22682665 23786146 27219198 35679219 36782700 45365330 47572292 54438396 59465365 68047995 71358438 90730660 113413325 118930730 136095990 142716876 178396095 226826650 237861460 272191980 297326825 340239975 356792190 440043701 453653300 594653650 680479950 713584380 880087402 891980475 1189307300 1320131103 1360959900 1760174804 1783960950 2200218505 2640262206 3567921900 4400437010 5280524412 6600655515 8800874020 11001092525 13201311030 22002185050 26402622060 33003277575 44004370100 66006555150 132013110300