Base | Representation |
---|---|
bin | 11110000001000011001100… |
… | …011001100001111010110111 |
3 | 122022102101000212101101121101 |
4 | 132001003030121201322313 |
5 | 114300402214234220310 |
6 | 1144434103535030531 |
7 | 36543443454604000 |
oct | 3601031431417267 |
9 | 568371025341541 |
10 | 132013544054455 |
11 | 390776a203a648 |
12 | 1298113896b447 |
13 | 5887a92b2945b |
14 | 24856bd75a1a7 |
15 | 103de9664443a |
hex | 7810cc661eb7 |
132013544054455 has 16 divisors (see below), whose sum is σ = 184741985851200. Its totient is φ = 90523573064736.
The previous prime is 132013544054377. The next prime is 132013544054479. The reversal of 132013544054455 is 554450445310231.
It is a happy number.
It is not a de Polignac number, because 132013544054455 - 235 = 131979184316087 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 38487912004 + ... + 38487915433.
It is an arithmetic number, because the mean of its divisors is an integer number (11546374115700).
Almost surely, 2132013544054455 is an apocalyptic number.
132013544054455 is a deficient number, since it is larger than the sum of its proper divisors (52728441796745).
132013544054455 is an frugal number, since it uses more digits than its factorization.
132013544054455 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 76975827463 (or 76975827449 counting only the distinct ones).
The product of its (nonzero) digits is 2880000, while the sum is 46.
Adding to 132013544054455 its reverse (554450445310231), we get a palindrome (686463989364686).
The spelling of 132013544054455 in words is "one hundred thirty-two trillion, thirteen billion, five hundred forty-four million, fifty-four thousand, four hundred fifty-five".
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