Base | Representation |
---|---|
bin | 11110000001000100101010… |
… | …100110000111011110010110 |
3 | 122022102112010000002220000210 |
4 | 132001010222212013132112 |
5 | 114300413433322143220 |
6 | 1144434524431350250 |
7 | 36543530564455206 |
oct | 3601045246073626 |
9 | 568375100086023 |
10 | 132015124412310 |
11 | 39078333115917 |
12 | 129814ba082386 |
13 | 5887c85375949 |
14 | 24857cd5ba406 |
15 | 103e03a2636e0 |
hex | 78112a987796 |
132015124412310 has 128 divisors (see below), whose sum is σ = 329285253888000. Its totient is φ = 33832233211392.
The previous prime is 132015124412263. The next prime is 132015124412317. The reversal of 132015124412310 is 13214421510231.
It is a super-2 number, since 2×1320151244123102 (a number of 29 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (30).
It is a Curzon number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (132015124412317) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 452933784 + ... + 453225156.
It is an arithmetic number, because the mean of its divisors is an integer number (2572541046000).
Almost surely, 2132015124412310 is an apocalyptic number.
132015124412310 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is a practical number, because each smaller number is the sum of distinct divisors of 132015124412310, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (164642626944000).
132015124412310 is an abundant number, since it is smaller than the sum of its proper divisors (197270129475690).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
132015124412310 is a wasteful number, since it uses less digits than its factorization.
132015124412310 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 293830.
The product of its (nonzero) digits is 5760, while the sum is 30.
Adding to 132015124412310 its reverse (13214421510231), we get a palindrome (145229545922541).
The spelling of 132015124412310 in words is "one hundred thirty-two trillion, fifteen billion, one hundred twenty-four million, four hundred twelve thousand, three hundred ten".
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