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13201745 = 52640349
BaseRepresentation
bin110010010111…
…000101010001
3220211201101112
4302113011101
511334423440
61150543105
7220133024
oct62270521
926751345
1013201745
1174a7737
124507a95
132972cab
141a791bb
15125b965
hexc97151

13201745 has 4 divisors (see below), whose sum is σ = 15842100. Its totient is φ = 10561392.

The previous prime is 13201723. The next prime is 13201759. The reversal of 13201745 is 54710231.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 1560001 + 11641744 = 1249^2 + 3412^2 .

It is a cyclic number.

It is not a de Polignac number, because 13201745 - 212 = 13197649 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 13201745.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1320170 + ... + 1320179.

It is an arithmetic number, because the mean of its divisors is an integer number (3960525).

Almost surely, 213201745 is an apocalyptic number.

It is an amenable number.

13201745 is a deficient number, since it is larger than the sum of its proper divisors (2640355).

13201745 is an equidigital number, since it uses as much as digits as its factorization.

13201745 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2640354.

The product of its (nonzero) digits is 840, while the sum is 23.

The square root of 13201745 is about 3633.4205647021. The cubic root of 13201745 is about 236.3435638101.

Adding to 13201745 its reverse (54710231), we get a palindrome (67911976).

The spelling of 13201745 in words is "thirteen million, two hundred one thousand, seven hundred forty-five".

Divisors: 1 5 2640349 13201745