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132020012311 = 1112001819301
BaseRepresentation
bin111101011110100000…
…0011000010100010111
3110121202200221111120121
41322331000120110113
54130334110343221
6140352115012411
712352402406035
oct1727500302427
9417680844517
10132020012311
1150a979452a0
122170529a107
13c5ac537aa5
146565893555
15367a37aa41
hex1ebd018517

132020012311 has 4 divisors (see below), whose sum is σ = 144021831624. Its totient is φ = 120018193000.

The previous prime is 132020012297. The next prime is 132020012393. The reversal of 132020012311 is 113210020231.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 132020012311 - 27 = 132020012183 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (132020012011) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6000909640 + ... + 6000909661.

It is an arithmetic number, because the mean of its divisors is an integer number (36005457906).

Almost surely, 2132020012311 is an apocalyptic number.

132020012311 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

132020012311 is a deficient number, since it is larger than the sum of its proper divisors (12001819313).

132020012311 is a wasteful number, since it uses less digits than its factorization.

132020012311 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 12001819312.

The product of its (nonzero) digits is 72, while the sum is 16.

Adding to 132020012311 its reverse (113210020231), we get a palindrome (245230032542).

The spelling of 132020012311 in words is "one hundred thirty-two billion, twenty million, twelve thousand, three hundred eleven".

Divisors: 1 11 12001819301 132020012311