Base | Representation |
---|---|
bin | 11110000001001001010110… |
… | …011001101010011011110000 |
3 | 122022110000002112202021211220 |
4 | 132001021112121222123300 |
5 | 114301004234000444212 |
6 | 1144441115511505040 |
7 | 36544066332064101 |
oct | 3601112631523360 |
9 | 568400075667756 |
10 | 132020154312432 |
11 | 3907a484395271 |
12 | 12982482688180 |
13 | 58885a7472bc9 |
14 | 2485b496223a8 |
15 | 103e231b2438c |
hex | 78125666a6f0 |
132020154312432 has 80 divisors (see below), whose sum is σ = 348319849769472. Its totient is φ = 43069000527360.
The previous prime is 132020154312427. The next prime is 132020154312463. The reversal of 132020154312432 is 234213451020231.
It is a happy number.
It is a super-2 number, since 2×1320201543124322 (a number of 29 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 132020154312393 and 132020154312402.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 69396807 + ... + 71273817.
Almost surely, 2132020154312432 is an apocalyptic number.
132020154312432 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
132020154312432 is an abundant number, since it is smaller than the sum of its proper divisors (216299695457040).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
132020154312432 is a wasteful number, since it uses less digits than its factorization.
132020154312432 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1908246 (or 1908240 counting only the distinct ones).
The product of its (nonzero) digits is 34560, while the sum is 33.
The spelling of 132020154312432 in words is "one hundred thirty-two trillion, twenty billion, one hundred fifty-four million, three hundred twelve thousand, four hundred thirty-two".
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