1320202011023 has 4 divisors (see below), whose sum is σ = 1508802298320. Its totient is φ = 1131601723728.

The previous prime is 1320202011017. The next prime is 1320202011041. The reversal of 1320202011023 is 3201102020231.

It is a semiprime because it is the product of two primes.

It is a de Polignac number, because none of the positive numbers 2^k-1320202011023 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1320202010992 and 1320202011010.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1320202011013) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 94300143638 + ... + 94300143651.

It is an arithmetic number, because the mean of its divisors is an integer number (377200574580).

Almost surely, 2^{1320202011023} is an apocalyptic number.

1320202011023 is a deficient number, since it is larger than the sum of its proper divisors (188600287297).

1320202011023 is an equidigital number, since it uses as much as digits as its factorization.

1320202011023 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 188600287296.

The product of its (nonzero) digits is 144, while the sum is 17.

Adding to 1320202011023 its reverse (3201102020231), we get a palindrome (4521304031254).

The spelling of 1320202011023 in words is "one trillion, three hundred twenty billion, two hundred two million, eleven thousand, twenty-three".