Base | Representation |
---|---|
bin | 10011001101100010001… |
… | …110110010100011100101 |
3 | 11200012200012212101210111 |
4 | 103031202032302203211 |
5 | 133112233432113013 |
6 | 2450254244053021 |
7 | 164244601244146 |
oct | 23154216624345 |
9 | 4605605771714 |
10 | 1320203004133 |
11 | 4699931a6222 |
12 | 193a45394171 |
13 | 9765786b860 |
14 | 47c807d5acd |
15 | 2451c8e073d |
hex | 133623b28e5 |
1320203004133 has 8 divisors (see below), whose sum is σ = 1421767424000. Its totient is φ = 1218640061808.
The previous prime is 1320203004067. The next prime is 1320203004137. The reversal of 1320203004133 is 3314003020231.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a de Polignac number, because none of the positive numbers 2k-1320203004133 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1320203004137) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2095708 + ... + 2651866.
It is an arithmetic number, because the mean of its divisors is an integer number (177720928000).
Almost surely, 21320203004133 is an apocalyptic number.
1320203004133 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
It is an amenable number.
1320203004133 is a deficient number, since it is larger than the sum of its proper divisors (101564419867).
1320203004133 is a wasteful number, since it uses less digits than its factorization.
1320203004133 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 738771.
The product of its (nonzero) digits is 1296, while the sum is 22.
Adding to 1320203004133 its reverse (3314003020231), we get a palindrome (4634206024364).
The spelling of 1320203004133 in words is "one trillion, three hundred twenty billion, two hundred three million, four thousand, one hundred thirty-three".
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