Search a number
-
+
13202031122021 = 71886004446003
BaseRepresentation
bin1100000000011101011001…
…1000000001011001100101
31201202002202020200220101102
43000013112120001121211
53212300224431401041
644024532424405445
72531546431661060
oct300072630013145
951662666626342
1013202031122021
11422aa4a434a35
121592785616885
13749c3ba2a531
14338da5b838d7
1517d6360ba09b
hexc01d6601665

13202031122021 has 4 divisors (see below), whose sum is σ = 15088035568032. Its totient is φ = 11316026676012.

The previous prime is 13202031121991. The next prime is 13202031122089. The reversal of 13202031122021 is 12022113020231.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13202031122021 - 230 = 13200957380197 is a prime.

It is a super-2 number, since 2×132020311220212 (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13202031121984 and 13202031122002.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13202031122921) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 943002222995 + ... + 943002223008.

It is an arithmetic number, because the mean of its divisors is an integer number (3772008892008).

Almost surely, 213202031122021 is an apocalyptic number.

It is an amenable number.

13202031122021 is a deficient number, since it is larger than the sum of its proper divisors (1886004446011).

13202031122021 is an equidigital number, since it uses as much as digits as its factorization.

13202031122021 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1886004446010.

The product of its (nonzero) digits is 288, while the sum is 20.

Adding to 13202031122021 its reverse (12022113020231), we get a palindrome (25224144142252).

The spelling of 13202031122021 in words is "thirteen trillion, two hundred two billion, thirty-one million, one hundred twenty-two thousand, twenty-one".

Divisors: 1 7 1886004446003 13202031122021