Base | Representation |
---|---|
bin | 1100000000011110001100… |
… | …0000010010011011110001 |
3 | 1201202010022000101122000111 |
4 | 3000013203000102123301 |
5 | 3212301143202113040 |
6 | 44025005434021321 |
7 | 2531554613644156 |
oct | 300074300223361 |
9 | 51663260348014 |
10 | 13202243004145 |
11 | 4230048aa3128 |
12 | 1592824577841 |
13 | 749c738b4c80 |
14 | 338dc5d7a22d |
15 | 17d6499bedea |
hex | c01e30126f1 |
13202243004145 has 16 divisors (see below), whose sum is σ = 17959326517440. Its totient is φ = 9236225064384.
The previous prime is 13202243004143. The next prime is 13202243004151. The reversal of 13202243004145 is 54140034220231.
It is a cyclic number.
It is not a de Polignac number, because 13202243004145 - 21 = 13202243004143 is a prime.
It is not an unprimeable number, because it can be changed into a prime (13202243004143) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 5345036419 + ... + 5345038888.
It is an arithmetic number, because the mean of its divisors is an integer number (1122457907340).
Almost surely, 213202243004145 is an apocalyptic number.
It is an amenable number.
13202243004145 is a deficient number, since it is larger than the sum of its proper divisors (4757083513295).
13202243004145 is a wasteful number, since it uses less digits than its factorization.
13202243004145 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 10690075344.
The product of its (nonzero) digits is 23040, while the sum is 31.
Adding to 13202243004145 its reverse (54140034220231), we get a palindrome (67342277224376).
The spelling of 13202243004145 in words is "thirteen trillion, two hundred two billion, two hundred forty-three million, four thousand, one hundred forty-five".
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