Base | Representation |
---|---|
bin | 10011001101100100101… |
… | …011001100010010110101 |
3 | 11200012210002000102001212 |
4 | 103031210223030102311 |
5 | 133112324431112041 |
6 | 2450302310531205 |
7 | 164245606605305 |
oct | 23154453142265 |
9 | 4605702012055 |
10 | 1320244004021 |
11 | 469a0435a028 |
12 | 193a57066b05 |
13 | 976631c5547 |
14 | 47c86029605 |
15 | 245212dd8eb |
hex | 13364acc4b5 |
1320244004021 has 8 divisors (see below), whose sum is σ = 1325645129088. Its totient is φ = 1314844000000.
The previous prime is 1320244003999. The next prime is 1320244004039. The reversal of 1320244004021 is 1204004420231.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1320244004021 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1320244004071) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2121941 + ... + 2672661.
It is an arithmetic number, because the mean of its divisors is an integer number (165705641136).
Almost surely, 21320244004021 is an apocalyptic number.
It is an amenable number.
1320244004021 is a deficient number, since it is larger than the sum of its proper divisors (5401125067).
1320244004021 is an equidigital number, since it uses as much as digits as its factorization.
1320244004021 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 560523.
The product of its (nonzero) digits is 1536, while the sum is 23.
Adding to 1320244004021 its reverse (1204004420231), we get a palindrome (2524248424252).
The spelling of 1320244004021 in words is "one trillion, three hundred twenty billion, two hundred forty-four million, four thousand, twenty-one".
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