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132025012303035 = 358801667486869
BaseRepresentation
bin11110000001001101110111…
…111101011011010010111011
3122022110110122002220210010210
4132001031313331123102323
5114301044211122144120
61144443241531242203
736544330611242025
oct3601156775332273
9568413562823123
10132025012303035
1139081547618535
12129833b95a9363
135888b9ca6c967
14248608a8b9015
15103e418378ce0
hex781377f5b4bb

132025012303035 has 8 divisors (see below), whose sum is σ = 211240019684880. Its totient is φ = 70413339894944.

The previous prime is 132025012303021. The next prime is 132025012303043. The reversal of 132025012303035 is 530303210520231.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 132025012303035 - 27 = 132025012302907 is a prime.

It is a super-2 number, since 2×1320250123030352 (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 132025012302993 and 132025012303011.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4400833743420 + ... + 4400833743449.

It is an arithmetic number, because the mean of its divisors is an integer number (26405002460610).

Almost surely, 2132025012303035 is an apocalyptic number.

132025012303035 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

132025012303035 is a deficient number, since it is larger than the sum of its proper divisors (79215007381845).

132025012303035 is an equidigital number, since it uses as much as digits as its factorization.

132025012303035 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8801667486877.

The product of its (nonzero) digits is 16200, while the sum is 30.

Adding to 132025012303035 its reverse (530303210520231), we get a palindrome (662328222823266).

The spelling of 132025012303035 in words is "one hundred thirty-two trillion, twenty-five billion, twelve million, three hundred three thousand, thirty-five".

Divisors: 1 3 5 15 8801667486869 26405002460607 44008337434345 132025012303035