1320301010141 has 4 divisors (see below), whose sum is σ = 1323364353984. Its totient is φ = 1317237666300.

The previous prime is 1320301010113. The next prime is 1320301010153. The reversal of 1320301010141 is 1410101030231.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1320301010141 is a prime.

It is a super-3 number, since 3×1320301010141³ (a number of 37 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1320301210141) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1531671275 + ... + 1531672136.

It is an arithmetic number, because the mean of its divisors is an integer number (330841088496).

Almost surely, 2^{1320301010141} is an apocalyptic number.

It is an amenable number.

1320301010141 is a deficient number, since it is larger than the sum of its proper divisors (3063343843).

1320301010141 is an equidigital number, since it uses as much as digits as its factorization.

1320301010141 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3063343842.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 1320301010141 its reverse (1410101030231), we get a palindrome (2730402040372).

The spelling of 1320301010141 in words is "one trillion, three hundred twenty billion, three hundred one million, ten thousand, one hundred forty-one".