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132032505030373 is a prime number
BaseRepresentation
bin11110000001010100110110…
…100011111010011011100101
3122022111011222021210202202201
4132001110312203322123211
5114301210032241432443
61144450521230334501
736545014362335113
oct3601246643723345
9568434867722681
10132032505030373
1139084742011482
121298494a95a431
1358897c518262c
14248659ba56ab3
15103e70607134d
hex7815368fa6e5

132032505030373 has 2 divisors, whose sum is σ = 132032505030374. Its totient is φ = 132032505030372.

The previous prime is 132032505030227. The next prime is 132032505030401. The reversal of 132032505030373 is 373030505230231.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 130075690135329 + 1956814895044 = 11405073^2 + 1398862^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-132032505030373 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (132032505036373) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66016252515186 + 66016252515187.

It is an arithmetic number, because the mean of its divisors is an integer number (66016252515187).

Almost surely, 2132032505030373 is an apocalyptic number.

It is an amenable number.

132032505030373 is a deficient number, since it is larger than the sum of its proper divisors (1).

132032505030373 is an equidigital number, since it uses as much as digits as its factorization.

132032505030373 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 170100, while the sum is 37.

The spelling of 132032505030373 in words is "one hundred thirty-two trillion, thirty-two billion, five hundred five million, thirty thousand, three hundred seventy-three".