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132032505030401 is a prime number
BaseRepresentation
bin11110000001010100110110…
…100011111010011100000001
3122022111011222021210202210202
4132001110312203322130001
5114301210032241433101
61144450521230334545
736545014362335153
oct3601246643723401
9568434867722722
10132032505030401
11390847420114a8
121298494a95a455
1358897c5182651
14248659ba56ad3
15103e70607136b
hex7815368fa701

132032505030401 has 2 divisors, whose sum is σ = 132032505030402. Its totient is φ = 132032505030400.

The previous prime is 132032505030373. The next prime is 132032505030403. The reversal of 132032505030401 is 104030505230231.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 100854296805376 + 31178208225025 = 10042624^2 + 5583745^2 .

It is an emirp because it is prime and its reverse (104030505230231) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 132032505030401 - 226 = 132032437921537 is a prime.

Together with 132032505030403, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (132032505030403) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66016252515200 + 66016252515201.

It is an arithmetic number, because the mean of its divisors is an integer number (66016252515201).

Almost surely, 2132032505030401 is an apocalyptic number.

It is an amenable number.

132032505030401 is a deficient number, since it is larger than the sum of its proper divisors (1).

132032505030401 is an equidigital number, since it uses as much as digits as its factorization.

132032505030401 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 10800, while the sum is 29.

The spelling of 132032505030401 in words is "one hundred thirty-two trillion, thirty-two billion, five hundred five million, thirty thousand, four hundred one".