Base | Representation |
---|---|
bin | 1100000000100011000011… |
… | …1010100000101100101011 |
3 | 1201202020200002221121200002 |
4 | 3000020300322200230223 |
5 | 3212311332312100210 |
6 | 44025343245533215 |
7 | 2531632165121645 |
oct | 300106072405453 |
9 | 51666602847602 |
10 | 13203550112555 |
11 | 4230659906010 |
12 | 1592b2a27420b |
13 | 74a12163b5ba |
14 | 3390ab7cb895 |
15 | 17d6c46164a5 |
hex | c0230ea0b2b |
13203550112555 has 8 divisors (see below), whose sum is σ = 17284647420144. Its totient is φ = 9602581900000.
The previous prime is 13203550112479. The next prime is 13203550112561. The reversal of 13203550112555 is 55521105530231.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 13203550112555 - 216 = 13203550047019 is a prime.
It is a Duffinian number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 120032273696 + ... + 120032273805.
It is an arithmetic number, because the mean of its divisors is an integer number (2160580927518).
Almost surely, 213203550112555 is an apocalyptic number.
13203550112555 is a deficient number, since it is larger than the sum of its proper divisors (4081097307589).
13203550112555 is a wasteful number, since it uses less digits than its factorization.
13203550112555 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 240064547517.
The product of its (nonzero) digits is 112500, while the sum is 38.
Adding to 13203550112555 its reverse (55521105530231), we get a palindrome (68724655642786).
The spelling of 13203550112555 in words is "thirteen trillion, two hundred three billion, five hundred fifty million, one hundred twelve thousand, five hundred fifty-five".
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