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1320434111 is a prime number
BaseRepresentation
bin100111010110100…
…0011100110111111
310102000122000002002
41032231003212333
510201012342421
6335005252515
744502335063
oct11655034677
93360560062
101320434111
11618394767
1230a26413b
13180740b79
14c751daa3
157adc9b0b
hex4eb439bf

1320434111 has 2 divisors, whose sum is σ = 1320434112. Its totient is φ = 1320434110.

The previous prime is 1320434099. The next prime is 1320434123. The reversal of 1320434111 is 1114340231.

It is a balanced prime because it is at equal distance from previous prime (1320434099) and next prime (1320434123).

It is an emirp because it is prime and its reverse (1114340231) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1320434111 - 218 = 1320171967 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1320434161) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 660217055 + 660217056.

It is an arithmetic number, because the mean of its divisors is an integer number (660217056).

Almost surely, 21320434111 is an apocalyptic number.

1320434111 is a deficient number, since it is larger than the sum of its proper divisors (1).

1320434111 is an equidigital number, since it uses as much as digits as its factorization.

1320434111 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 288, while the sum is 20.

The square root of 1320434111 is about 36337.7780140724. The cubic root of 1320434111 is about 1097.0815505819.

Adding to 1320434111 its reverse (1114340231), we get a palindrome (2434774342).

The spelling of 1320434111 in words is "one billion, three hundred twenty million, four hundred thirty-four thousand, one hundred eleven".