Base | Representation |
---|---|
bin | 11110000001011111110101… |
… | …110111000011001110110010 |
3 | 122022112022102121110101010210 |
4 | 132001133311313003032302 |
5 | 114301403213413230002 |
6 | 1144500152132404550 |
7 | 36545612646514116 |
oct | 3601376567031662 |
9 | 568468377411123 |
10 | 132044304430002 |
11 | 39089747510018 |
12 | 129870a2476756 |
13 | 588a9558ac7c3 |
14 | 2486d9ab77746 |
15 | 103eb96db996c |
hex | 7817f5dc33b2 |
132044304430002 has 48 divisors (see below), whose sum is σ = 280847187526752. Its totient is φ = 41379894429120.
The previous prime is 132044304429977. The next prime is 132044304430009. The reversal of 132044304430002 is 200034403440231.
It is a happy number.
It is a super-4 number, since 4×1320443044300024 (a number of 58 digits) contains 4444 as substring.
It is not an unprimeable number, because it can be changed into a prime (132044304430009) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 232396723 + ... + 232964214.
It is an arithmetic number, because the mean of its divisors is an integer number (5850983073474).
Almost surely, 2132044304430002 is an apocalyptic number.
132044304430002 is an abundant number, since it is smaller than the sum of its proper divisors (148802883096750).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
132044304430002 is a wasteful number, since it uses less digits than its factorization.
132044304430002 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 465361111 (or 465361092 counting only the distinct ones).
The product of its (nonzero) digits is 27648, while the sum is 30.
Adding to 132044304430002 its reverse (200034403440231), we get a palindrome (332078707870233).
The spelling of 132044304430002 in words is "one hundred thirty-two trillion, forty-four billion, three hundred four million, four hundred thirty thousand, two".
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