132052441400113 has 4 divisors (see below), whose sum is σ = 142210321507828. Its totient is φ = 121894561292400.

The previous prime is 132052441400057. The next prime is 132052441400197. The reversal of 132052441400113 is 311004144250231.

It is a happy number.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 48945023429184 + 83107417970929 = 6996072^2 + 9116327^2 .

It is not a de Polignac number, because 132052441400113 - 2²⁵ = 132052407845681 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (132052441400213) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5078940053838 + ... + 5078940053863.

It is an arithmetic number, because the mean of its divisors is an integer number (35552580376957).

Almost surely, 2^{132052441400113} is an apocalyptic number.

132052441400113 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

132052441400113 is a deficient number, since it is larger than the sum of its proper divisors (10157880107715).

132052441400113 is a wasteful number, since it uses less digits than its factorization.

132052441400113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10157880107714.

The product of its (nonzero) digits is 11520, while the sum is 31.

Adding to 132052441400113 its reverse (311004144250231), we get a palindrome (443056585650344).

The spelling of 132052441400113 in words is "one hundred thirty-two trillion, fifty-two billion, four hundred forty-one million, four hundred thousand, one hundred thirteen".