132052520544340 has 96 divisors (see below), whose sum is σ = 304222929010560. Its totient is φ = 47748865113600.

The previous prime is 132052520544257. The next prime is 132052520544443. The reversal of 132052520544340 is 43445025250231.

It is a super-3 number, since 3×132052520544340³ (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 132052520544293 and 132052520544302.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1233840030 + ... + 1233947050.

It is an arithmetic number, because the mean of its divisors is an integer number (3168988843860).

Almost surely, 2^{132052520544340} is an apocalyptic number.

132052520544340 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 132052520544340, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (152111464505280).

132052520544340 is an abundant number, since it is smaller than the sum of its proper divisors (172170408466220).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

132052520544340 is a wasteful number, since it uses less digits than its factorization.

132052520544340 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 138553 (or 138551 counting only the distinct ones).

The product of its (nonzero) digits is 576000, while the sum is 40.

Adding to 132052520544340 its reverse (43445025250231), we get a palindrome (175497545794571).

The spelling of 132052520544340 in words is "one hundred thirty-two trillion, fifty-two billion, five hundred twenty million, five hundred forty-four thousand, three hundred forty".