Base | Representation |
---|---|
bin | 1100000000101010000110… |
… | …1001001110001001101000 |
3 | 1201202102112220202020220120 |
4 | 3000022201221032021220 |
5 | 3212324220444434134 |
6 | 44030255050523240 |
7 | 2532030101625453 |
oct | 300124151161150 |
9 | 51672486666816 |
10 | 13205441405544 |
11 | 423143a454473 |
12 | 1593377736520 |
13 | 74a363413c8b |
14 | 33920aa6a49a |
15 | 17d7856a4649 |
hex | c02a1a4e268 |
13205441405544 has 64 divisors (see below), whose sum is σ = 35560234967040. Its totient is φ = 4074610246080.
The previous prime is 13205441405539. The next prime is 13205441405671. The reversal of 13205441405544 is 44550414450231.
It is a junction number, because it is equal to n+sod(n) for n = 13205441405496 and 13205441405505.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 385836132 + ... + 385870355.
It is an arithmetic number, because the mean of its divisors is an integer number (555628671360).
Almost surely, 213205441405544 is an apocalyptic number.
It is an amenable number.
13205441405544 is an abundant number, since it is smaller than the sum of its proper divisors (22354793561496).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13205441405544 is a wasteful number, since it uses less digits than its factorization.
13205441405544 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 771706550 (or 771706546 counting only the distinct ones).
The product of its (nonzero) digits is 768000, while the sum is 42.
Adding to 13205441405544 its reverse (44550414450231), we get a palindrome (57755855855775).
The spelling of 13205441405544 in words is "thirteen trillion, two hundred five billion, four hundred forty-one million, four hundred five thousand, five hundred forty-four".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.104 sec. • engine limits •