Base | Representation |
---|---|
bin | 10011001101111100100… |
… | …011001010001000011111 |
3 | 11200020210222201022111112 |
4 | 103031330203022020133 |
5 | 133114140001114244 |
6 | 2450410140012235 |
7 | 164261542316321 |
oct | 23157443121037 |
9 | 4606728638445 |
10 | 1320644551199 |
11 | 46a09a469056 |
12 | 193b4923107b |
13 | 976c8198bcc |
14 | 47cc32d3611 |
15 | 2454655e39e |
hex | 1337c8ca21f |
1320644551199 has 4 divisors (see below), whose sum is σ = 1378063879536. Its totient is φ = 1263225222864.
The previous prime is 1320644551189. The next prime is 1320644551201. The reversal of 1320644551199 is 9911554460231.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1320644551199 is a prime.
It is a super-2 number, since 2×13206445511992 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1320644551159) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 28709664134 + ... + 28709664179.
It is an arithmetic number, because the mean of its divisors is an integer number (344515969884).
Almost surely, 21320644551199 is an apocalyptic number.
1320644551199 is a deficient number, since it is larger than the sum of its proper divisors (57419328337).
1320644551199 is an equidigital number, since it uses as much as digits as its factorization.
1320644551199 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 57419328336.
The product of its (nonzero) digits is 1166400, while the sum is 50.
Adding to 1320644551199 its sum of digits (50), we get a square (1320644551249 = 11491932).
The spelling of 1320644551199 in words is "one trillion, three hundred twenty billion, six hundred forty-four million, five hundred fifty-one thousand, one hundred ninety-nine".
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